Independent work on similar terms.


CONTROL WORK No. 12
Option 1
A1. Open the brackets and find the value of the expression: 3.7 - (1.4 - 2.8)
a) - 20 aub) 5.8 mv) -x
A4. Simplify expressions:
a) 1.2 5xb)
c) - 12 (- x) y d) 25 ah (-4)

a) - (3a - 5c) + 3ab) 3 (2x + 8) - (5x + 2)
A6. Solve the equation: 12x - 7x = 30

a) 5a + x - 5a + xb) 6a - a - 9m + 6m - 3
23,6 + (14,5 – 30,1) – (6,8 + 1,9)
IN 2. Simplify the expression and find its value at m = 1.6.

a) 1.513 + 1.57b)

C1. For what values ​​of a is it true - a > a?
C2. Solve the equation: 0.6 (x + 7) - 0.5 (x - 3) = 6.8

CONTROL WORK No. 12
Coefficient. Bracket opening. Similar terms
Option 2
A1. Open the brackets and find the value of the expression: 3.2 - (1.1 - 2.3)
A2. Write down the expressions and underline the coefficient:
a) 15mxb) - 2.9mc) -a
A3. Find the coefficient of the product:
A4. Simplify expressions:
a) 0.5 2ab)
c) - 80.3 (- x) d) 15 (-3mn)
A5. Expand the brackets (if possible, give like terms):
a) 7a + (-4c + c) b) -2 (a-8) + 5.3a-2.7
A6. Solve the equation: 9x - 5x = 28
A7. Give like terms:
a) -8 x + 3y + y + 8xb) 5x + 2x - 10a + 8a -2
IN 1. Expand the brackets and find the meaning of the expression:
17,8 – (11,7 + 14,8) – (3,5 – 12,6)
IN 2. Simplify the expression and find its value at a = 2.1.
IN 3. Find expression values:
a) 3.5 2.4 - 3.5 1.4b)
In the tasks of part C, you must write a detailed solution
C1. For what values ​​of t is true t< – m?
C2. Solve the equation: 0.3 (x - 2) - 0.2 (x + 4) \u003d 0.6

CONTROL WORK No. 12
Coefficient. Bracket opening. Similar terms
Option 3
A1. Open the brackets and find the value of the expression: 2.4 - (6.2 - 3.7)
A2. Write down the expressions and underline the coefficient:
a) - 1.6ub) ayc) -mn
A3. Find the coefficient of the product:
A4. Simplify expressions:
a) -0.9 4ab)
c) -1.4х∙(-5) d) 17 (-6kn)
A5. Expand the brackets (if possible, give like terms):
a) -6-(8a-1)b) 2(5-2x)+12x-7
A6. Solve the equation: 7a - 2a = 30
A7. Give like terms:
a) 3ax + 4ax - 5 - 9axb) - 2y - 20 + 8y + y
IN 1. Expand the brackets and find the meaning of the expression:
23,8 – (11,7 – 14,5) + (- 32, 5 – 19,7)
IN 2. Simplify the expression and find its value at.
IN 3. Find expression values:
a) 4.75 3.2 + 3.2 3.25 b)
In the tasks of part C, you must write a detailed solution
C1. For what values ​​of c is true - c< c?
C2. Solve the equation: 0.5 (4 + x) - 0.4 (x - 3) \u003d 2.5

CONTROL WORK No. 12
Coefficient. Bracket opening. Similar terms
Option 4
A1. Open the brackets and find the value of the expression: 3.5 - (2.7 - 4.2) A2. Write down the expressions and underline the coefficient:
a) - 2.01 aub) ahb) -xy
A3. Find the coefficient of the product:
A4. Simplify expressions:
a) - 0.7 3ab)
c) –x ∙ (-5) ∙ 0.45 d) 21 (-7ac)
A5. Expand the brackets (if possible, give like terms):
a) -5 + (x-1) -7x b) -3 (a-7) + 5a-8
A6. Solve the equation: 2 x + 4 x = 30
A7. Give like terms:
a) 9xy + 3xy - 12 - xy b) 4a - 16 + 16 a - a
IN 1. Expand the brackets and find the meaning of the expression:
8,7 + (13,7 – 15,2) – (24,6 – 20,1)
IN 2. Simplify the expression and find its value at k = 3.5.
IN 3. Find expression values:
a) 0.90.8 - 0.8 0.8b)
In the tasks of part C, you must write a detailed solution
C1. For what values ​​of n is it true - n > n?
C2. Solve the equation: 0.4 (x - 9) - 0.3 (x + 2) = 0.7


Attached files

"Mathematics" No. 2 7/2002, 22/2003

OPTION 1

1 a) opening brackets: 34.4 - (18.1 - 5.6) + (-11.9 + 8); 2 . Simplify the expression: a) 4 t – 6t –3t + 7 + t; b) –8( k – 3) + 4(k – 2) – 2(3k + 1); in)
.
3 . Solve the equation: 0.6( at – 3) – 0,5(at – 1) = 1,5. 4 . The traveler traveled 3 hours by bus and 3 hours by train, covering a distance of 390 km during this time. Find the speed of the bus if it is three times the speed of the train. 5 . Find the roots of the equation (2.5 at – 4)(6at + 1,8) = 0.

OPTION 2

1 . Find the value of the expression: a) opening brackets: 28.3 + (-1.8 + 6) - (18.2 - 11.7); b) applying the distributive property of multiplication:

.

2 . Simplify the expression: a) 6 + 4 a – 5a + a – 7a; b) 5( P – 2) – 6(P + 3) – 3(2P – 9); in)
.
3 . Solve the equation: 0.8( X – 2) – 0,7(X – 1) = 2,7. 4 . Tourists traveled 270 km, moving 6 hours by boat and 3 hours by bus. What was the speed of the ship if it was half the speed of the bus? 5 . Find the roots of the equation (4.9 + 3.5 X)(7X – 2,8) = 0.

OPTION 3

1 . Find the value of the expression: a) opening brackets: 43.2 - (25.3 - 6.8) + (-14.7 + 7); b) applying the distributive property of multiplication:

.

2 . Simplify the expression: a) 3 P – 8P –5P + 2 + 2P; b) –3( a – 2) + 6(a – 4) – 4(3a + 2); in)
.
3 . Solve the equation: 0.4( a – 4) – 0,3(a – 3) = 1,7. 4 . The travelers sailed a 195 km path, moving 3 hours on a motor boat and 5 hours on a steamboat. What is the speed of the boat if it is half the speed of the boat? 5 . Find the roots of the equation (4.2 X – 6,3)(5X + 5,5) = 0.

OPTION 4

1 . Find the value of the expression: a) opening brackets: 56.7 + (-12.5 + 9) - (27.5 - 13.3); b) applying the distributive property of multiplication:

.

2 . Simplify the expression: a) 8 + 7 k – 3k + k – 11k; b) 4( with – 1) – 7(with + 5) – 2(3with + 8); in)
.
3 . Solve the equation: 0.9(b – 5) – 0,8(b – 2) = 2,3. 4 . The tourist rode a bicycle for 4 hours and walked for 3 hours, covering 60 km. Find the tourist's speed if it is three times less than his speed when cycling? 5 . Find the roots of the equation (6.2 X + 9,3)(4X – 3,6) = 0.
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